Math, asked by praseedkv23, 1 month ago

1. In pavallelogram ABCD the diagonals
AC and Bo intersect at o AC-65cm
BD = 7cm and LAOB-100°.
Construct the parallelogram​

Answers

Answered by mgame8182gmailcom
0

Answer:

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Answered by dchoudhary007
0

Answer:

Given:

AC = 9 cm, BD = 7 cm and ∠ AOB = 120

o

Steps for construction

Step 1 : Draw a rough diagram and mark the given measurements.

Step 2 : Draw a line segment AC = 9 cm.

Step 3 : Mark O the midpoint of

AC

.

Step 4 : Draw a line

XY

through O which makes ∠ AOY = 120

o

.

Step 5 : With O as centre and 3.5 cm as radius draw two arcs on

XY

on either sides of

AC

cutting

OX

at D and

OY

at B.

Step 6 : Join

AB

,

BC

,

CD

and

DA

. ABCD is the required parallelogram.

Step 7 : From D draw

DE

AB

and measure the length of DE. DE = h = 4 cm. AB = b = 7 cm.

Calculation of area:

In the parallelogram ABCD, b = 7 cm and h = 4 cm.

Area of the parallelogram ABCD = b *h = 7 *4 = 28 cm

2

.

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