1. In quadrilateral ACBD,
AC = AD and AB bisects ZA
(see Fig. 7.16). Show that A ABC = A ABD.
What can you say about BC and BD?
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Question :-
In quadrilateral ACBD, AC = AD and AB bisects ∠ A (see figure). Show that ∆ABC ≅ ∆ABD. What can you say about BC and BD?
Answer :-
In quadrilateral ACBD, we have AC = AD and AB being the bisector of ∠A.
Now, In ∆ABC and ∆ABD,
AC = AD (Given)
∠ CAB = ∠ DAB ( AB bisects ∠ CAB)
and AB = AB (Common)
∴ ∆ ABC ≅ ∆ABD (By SAS congruence axiom)
∴ BC = BD (By CPCT)
Plz mrk as brainliest ❤
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