Question

(1) In the adjoining figure
seg AD I seg BC, B-D-C.
Show that
AB+CDAC + BD.
B
D
In A ABD, AB - ADP-BD. Pythagoras Theorem
1. AD - AB-BD... (1)
= ADP + DC
In A ACD,
I=AC
= AC
AB
-
DC... from (1) and (ID)
AB+CD= AC+BD'.​

Answer 1

Answer:

not me you really asking to a wrong person I am good and science, social and gk

literally I am weak at maths