1.
In the adjoining figure, show that AC BDif AB=CD.
A B C D
DE
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Answered by
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Answer:
In ΔABC;AB+BC>AC
In ΔACD;CD+DA>AC
ΔBCD;BC+CD>BD
ΔABD;DA+AB>BD
By adding all these
2(AB+BC+CD+DA)>2(AC+BD)
(AB+BC+CD+DA)>(AC+BD).
Answered by
0
Answer:
In ΔABC;AB+BC>AC
In ΔACD;CD+DA>AC
ΔBCD;BC+CD>BD
ΔABD;DA+AB>BD
By adding all these
2(AB+BC+CD+DA)>2(AC+BD)
(AB+BC+CD+DA)>(AC+BD).
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