Question

1. In the figure, 2ABC = 90°. ZACB = 0, AB = 573 and BC = 5 then what is the value of 0. A 53 B C 5​

Answer 1

Step-by-step explanation:

Given ∠B=90

∘

,AB=28cm,BC=21cm

Area of shaded region=ar△ABC+area of semicircle AC-ar quarter circle BC

=

2

1

×BC×AB+

2

1

×π(

2

AC

)

2

−

4

1

×π(BC)

2

=[

2

1

×21×28]+[

2

1

×

7

22

×

4

1

(

28

2

+21

2

)

2

]−

4

1

×

7

22

×21×21

=294+[

28

11

×1225]−346.5

=294+481.25−346.5=428.75㎠