Question

1] In the figure AABC is right angled triangle AB=3, AC = 5 then find cos O.




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Answer 1

The diagram is in the attachment ⤴️

Answer ⤵️

In ∆ ABC,

AB=3

AC = 5

BC= 4

By Pythagoras theorem

AC²=BC²+BA²

BC²=AC²-BA²

BC²= 5²-3²

BC²= 25-9

BC²=16

BC= √16

BC= 4

Cos theta= Base/Hypotenuse

Cos theta= BC/AC

Cos theta= 4/3

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