Question

1) In the figure ABCD is a trapezium
Diagonal AC and BD intersect at M
Area of triangle ABC is 24 cm and area
of triangle AMB is 10 sq.cm.
a) Find the area of triangle BMC.
b) How much is the area of triangle AMD?
Write reason
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Answer 1

Answer:

(a). 14 sq. cm

Step-by-step explanation:

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Answer 2

Answer:

a) 14cm²

Step-by-step explanation:

Since all triangles with the same base and the 3rd vertex on a line parallel to the base have the same area,

Triangle ACB = Triangle ADB

Triangle AMB = 10cm² (common to both Triangles ACB and ADB)

SO, ACB-AMB= 14cm²

ADB-AMB= 14cm²