Question

1. In the figure alongside, ABCD is a rectangular groung of length 40m and breadth 30m. Rabin reached at C walking from A to B and B to C. But Nabin reached to C walking from A to C directly, who walked the shorter distance and by how much? i
in pythagoras theorem (pls send full process and if you send any improper answer you will get reported)

Answer 1

Answer:

Rabin walked (30 + 40)m.

= 70 metres

Nabin walked ✓(30² + 40²)m.

= ✓(900 + 1600)m

= ✓(2500)m

= 50m

Rabin walked more by 20m.