1. In the figure, DE || BC. If AD=4 cm,
DB = 8 cm and AC = 18 cm, find the
lengths of AE and EC.
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Answer:
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Step-by-step explanation:
Given: Δ ABC, DE ∥ BC, AD = 6 cm, DB = 9 cm and AE = 8 cm.
Required to find AC.
By using Thales Theorem, [As DE ∥ BC]
AD/BD = AE/CE
Let CE = x.
So then,
6/9 = 8/x
6x = 72 cm
x = 72/6 cm
x = 12 cm
∴ AC = AE + CE = 12 + 8 = 20.
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