Question

1. In the figure, given below, it is given that AB is
perpendicular to BD and is of length X metres.
DC = 30 m, ZADB = 30° and ZACB = 45°.
Without using tables, find X.​

Answer 1

Step-by-step explanation:

$in \: △ABC,  \\ AB/BC=tan \: 45° = 1 \\ So,BC=AB=X  \\ In△ABD, </p><p></p><p> \\ AB/BD=tan \: 30° \\ X/(30+X)=1/3 \\ 30+X= \sqrt{} 3X \\ X=30/( \sqrt{} 3−1)=30/(1.732−1)=30/0.732 </p><p></p><p></p><p></p><p></p><p></p><p></p><p></p><p></p><p></p><p></p><p></p><p></p><p></p><p></p><p></p><p></p><p> \\ Thus, X=40.98m</p><p></p><p>$