1) In the figure, RP=3 PK=6. Find the value of A(TRP): A(TPK)
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Given : RP=3 PK=6
To Find : A(TRP): A(TPK)
Solution:
Draw TM ⊥ RK ( RP , PK ) as RPK are collinear
TM = h
Area of triangle = (1/2) * base * Height
A(TRP) = (1/2) * RP * TM = (1/2) * 3 * h
A(TPK) = (1/2) * PK * TM = (1/2) * 6 * h
A(TRP) : A(TPK) = (1/2) * 3 * h : (1/2) * 6 * h
=> A(TRP) : A(TPK) = 1 : 2
A(TRP) : A(TPK) = 1 : 2
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