Question

1) In the figure, what is the area of the rectangle ABCD?
2) What type of the triangle is ABC?
3) Find the area of ABC.
4) In BEC, what is the length of the perpendicular from E to BC?
5) Find the area of BEC.
6) Draw another triangle of equal area with one side 6cm.​

Answer 1

1) Area of rectangle ABCD = l×b = 10×4 = 40 cm²

2) Triangle ABC is a right angle triangle because angel B = 90°

3) Area of ∆ABC = 1/2× base × height = 1/2×10×4

= 20cm²

4) it is of 4cm because when we draw perpendicular it will be parallel to CD

5) Area of BEC = 1/2 × b×h = 1/2×10×4 = 20cm²

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Answer 2

Answer:

1. Area of the rectangle ABCD is 40 sq. cm
2. ABC is a Right angle triangle
3. Area of ΔABC is $\frac{1}{2}$ × base × height  = 20 sq cm
4. Perpendicular length from E to BC is 4 cm
5. Area of ΔBEC is $\frac{1}{2}$ × base × height  = 20 sq cm

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