Math, asked by hetvithakur99, 25 days ago

1. In the figures below, find the value of 'x
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Answers

Answered by khushal2006panwar
0

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Answered by ItsAritraKar
1

Solution:-

i) ΔLMN is a right angled triangle .

So, (LM)² + (MN)² = (LN)²

or, 7² + 24² = x²

or, x² = 49 + 576

or, x² = 625

or, x = √625 = 25

ii) ΔQPR is also a right angled triangle .

So,(QP)² + (QR)² = (PR)²

or, 9² + x² = 41²

or, x² = 41² - 9²

or, x² = 1681 - 81

or, x² = 1600

or, x = √1600

or, x = 40

iii) ΔEFD is also a right angled triangle .

So,(FD)² + (ED)² = (EF)²

or, 8² + x² = 17²

or, x² = 17² - 8²

or, x² = 289 - 64

or, x² = 225

or, x = √225

or, x = 15

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