Question

1. In the following figure, AB || CD intersected by
a transversal XY then find the angles:
(a) angleBPQ
(b) anglePOD
(c) angleXPB
​

Answer 1

Answer:

angleBPQ =150 bez sum of angle APQand BPQ is 180

angle PQD =30 bez AB is parallel to CD and angle APQ =PQD by alternate angles

angle XPB =30 bez sum of angle XPB AND BPQ is equal to 180