Question

1.
In the following figure, AOB is a straight angle. OQ
is the bisector of AOC and OP is the bisector of BOC.
If AOC = 60°, then find i) BOC ii) POQ.​

Answer 1

Step-by-step explanation:

Here OP bisect ∠BOC

∴∠POC=∠BOP …………(i)

and OQ bisect ∠AOC

∴∠AOQ=∠COQ …………….(ii)

and ∠AOB=180

o

[∵AOB is a straight line]

⇒∠BOP+∠DOC+∠COQ+∠AOQ=180

o

⇒∠POC+∠POC+∠COQ+∠COQ=180

o

[using (i) & (ii)]

⇒2∠POC+2∠COQ=480

o

⇒2(∠POC+∠COQ)=180

o

⇒2∠POQ=180

o

⇒∠POQ=90

o

.