Question

1. In the given figure, AB || CD, LFAE +90", ZAFE - 40", find ECD.​

Answer 1

Answer:

By angle sum property in triangle FAE.

90o + 40o + AEF = 180o

Or, AEF = 50o

CEB = AEF = 50o (vertically opp. angles)

ECD + CEB = 180o

Or, ECD + 50o = 180o

ECD = 130o