Question

1.
In
the
given
figure
,
ABCD
is
a
parallelogram
angle A
=
70
°
.
Calculate
angleB
,
angleC
and
angle D.
​

Answer 1

Answer:

can't understand your question...send a pic of your question also

Answer 2

$In \: a \: parallelogram, \\ opposite \: angles \: are \: always \: equal.</p><p></p><p> \\ ⇒∠A=∠C and ∠B=∠D</p><p></p><p> \: \\ as ∠A= {70}^{o} \\ ⇒∠C= {70}^{o} </p><p></p><p> \\ Also ∠A+∠B+∠C+∠D = {360}^{o} </p><p></p><p> \\ ⇒∠B+∠D= {360}^{o} − {140}^{o} </p><p></p><p> \\ ⇒2∠B= {220}^{o} </p><p></p><p> \\ ⇒∠B= {110}^{o} </p><p></p><p> \\ ⇒D= {110}^{o} </p><p></p><p>$