Question

1 In the given figure, QR is a common tangent
to the given circles, touching externally at the
point T. The tangent at T meets QR at P. If
PT = 3.8 cm, then the length of QR(in cm) is
Į APR
(a) 3.8
(b) 7.6
(6) 5.7
(d) 1.9​

Answer 1

Step-by-step explanation:

Lengths of the tangents drawn from an external point to a circle are equal. 

∴QP=PT=3.8cm............(i)

PR=PT=3.8cm............(ii)

From equations (i) and (ii):

QP = PR = 3.8 cm

But, QR = QP + PR

∴ QR = 3.8 + 3.8

QR = 7.6 cm