Question

1. In the measurement of three quantities A.B.C it is
stated as A= 25 0.005 B = ito.001, C= 4+0:01. Then
the percentage error in P- A
B​

Answer 1

Given that,

In the measurement of three quantities A.B.C

The function of P is

$P=\dfrac{AB}{C}$

The value of A = 25±0.005

The value of B = 20±0.001

The value of C = 4±0.01

We need to calculate the percentage error in P

Using formula of error

$\dfrac{\Delta P}{P}\times100=\dfrac{\Delta A}{A}\times100+\dfrac{\Delta B}{B}\times100+\dfrac{\Delta C}{C}\times100$

Put the value into the formula

$\dfrac{\Delta P}{P}\times100=\dfrac{0.005}{25}\times100+\dfrac{0.001}{20}\times100+\dfrac{0.01}{4}\times100$

$\dfrac{\Delta P}{P}\times100=0.275\%\approx0.3\%$

Hence,  The percentage error in P is 0.3 %.