Question

1) In the
the given figure , ABIICD and I is
transversal find the values of x and y..
​

Answer 1

Answer:

x = 122degree and,

y = 63degree

Step-by-step explanation:

( y - 5)degree + (2y - 4)degree = 180 degree

(because. sum of the interior angles on the same side of transversal is 180degree)

Now,

y-5+2y-4=180

y+2y-5-4=180

3y-9=180

3y=180+9

3y=189

y=189÷3

y=63degree.

Now,

(2y-4)degree =2×63-4=122degree.

Then,

x=122degree ( because corresponding angles are equal).

Therefore,

x = 122degree and

y = 63degree.

Answer 2

Answer:

X+Y-5=180 (SUPPLEMENTARY ANGLE)---(1)

2Y-4=180 (SUPPLEMENTARY ANGLE)---(2)

X+Y-5= 2Y-4

X+Y-2Y= -4+5

X-Y=1

X=Y+1---(3)

SUB. X=Y+1 IN EQN.(1),

(1+Y)+Y-5=180

1+2Y-5=180

2Y-4=180

2Y=180

Y=90

X=1+90

X=91

Step-by-step explanation:

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