Question

1.
In the triangle ABC, D is the midpoint of the side BC; From the point D, the parallel
straight lines of CA and BA intersect the sides BA and CA at the points E and F respectively.
BC.
Let us prove that, EF = 1/2 BC.
2​

Answer 1

Step-by-step explanation:

Since,D is the midpoint of bc and

DF parallel to AB

so, F is also the mid point of AC by converse of mid point theorem.

then AF=FC......(i)

also, D is the mid point of BC and

ED parallel to AC

so, E is also mid point of AB by coverse of mid point theorem

then AE = EB .....(ii)

from equation i and ii we have:

AF/FC=AE/EB

so now by converse of midpoint theorem

EF is parallel to BC and EF=1/2 BC.

DRAW A PROPER FIGURE U WILL GOT THE POINT MORE CLEARLY.

I hope it will helpful to u.

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