Question

1. In the triangle shown below find the value of x and ∠P

Answer 1

Answer:

By angle sum property of a trinagle, angle P+Q+R = 180°

So

2x+12+32+62 = 180°

2x+106 = 180°

2x = 180 - 106

2x = 74

x = 74/2

x = 37

:)

Angle P = 2x+12

Angle P = 2×37+12 = 86

:)

Answer 2

Answer:

In ∆PQR,

<Q+<P+<R=180°

62°+(2x+12)°+32°=180°

2x=180°-106°

2x=74°

x=37°

and <P=2x+12

<P=2×37+12

<P=86.