1. In the triangle shown below find the value of x and ∠P
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2
Answer:
By angle sum property of a trinagle, angle P+Q+R = 180°
So
2x+12+32+62 = 180°
2x+106 = 180°
2x = 180 - 106
2x = 74
x = 74/2
x = 37
:)
Angle P = 2x+12
Angle P = 2×37+12 = 86
:)
Answered by
0
Answer:
In ∆PQR,
<Q+<P+<R=180°
62°+(2x+12)°+32°=180°
2x=180°-106°
2x=74°
x=37°
and <P=2x+12
<P=2×37+12
<P=86.
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