Question

1)In △\triangle△ ABC, AB = AC and AL is perpendicular to BC at L. In △\triangle△ DEF, DE = DF and DM is perpendicular to EF at M.If (area of △\triangle△ ABC) (area of △\triangle△ DEF) = 9:25, then DM+ADM−AL\frac{DM + AL}{DM - AL}DM−ADM+AL​ is equal to

2) if 2sinθ +15cos2θ=7 0∘ θ 90 then tanθ+ cosθ+ secθ+ tanθ ?

Answer 1

Answer:

this is your wrong question

Answer 2

Answer:

Here is ur sol....

Step-by-step explanation:

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