Question

1. In triangle ABC, angleA: angleB: angleC = 3:4:5. Find the
measure of each angle of angle ABC.​

Answer 1

Step-by-step explanation:

In the △ABC according to the given condition we have ∠B−∠C=30 o

⇒∠B=30 o+∠C∠A−∠B=15 o

⇒∠A=15 o+∠B=45 o +∠C

Now, using the property that sum of all the interior angle of a triangle is 180 o

we get∠A+∠B+∠C=180 o

⇒45 o +∠C+30 o +∠C+∠C=180 o

⇒3∠C=105 o

⇒∠C=35 o

∴∠A=80o,∠B=65o ,∠C=35o

Answer 2

3x=3(15)=45 degree

4x=4(15)=60 degree

5x=5(15)=75 degree

Step-by-step explanation:

Ratio is - 3:4:5

let the common multiple be 'x'

so the ratio is 3x,4x and 5x

so by angle sum property of triangle

3x+4x+5x=180

12x=180

x=180/12

x= 15

therefore the angles are

3x=3(15)=45 degree

4x=4(15)=60 degree

5x=5(15)=75 degree