1. In triangle ABC, D is any point on BC.
Prove that : AB + BC + AC > 2 AD.
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Step-by-step explanation:
truangleABD
truangleABDAB+BD > AD…………….(1)
truangleABDAB+BD > AD…………….(1)In triangle ADC
truangleABDAB+BD > AD…………….(1)In triangle ADCDC+CA > AD…………….(2)
truangleABDAB+BD > AD…………….(1)In triangle ADCDC+CA > AD…………….(2)On adding (1) & (2)
truangleABDAB+BD > AD…………….(1)In triangle ADCDC+CA > AD…………….(2)On adding (1) & (2)AB+BD+DC+CA > 2AD
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