Question

1)In triangle ABC Seg BD is altitude of Side Ac then angle ADB=?
=> ? ​

Answer 1

Solution

In tringle ABD & ACD

AB=AC (GIVEN)

ANGLE ADB=ANGLE ADC(BOTH ARE RIGHT ANGLES)

AD=AD(COMMON)

SO BOTH THE TRIANGLES ARE CONGRUENT

THEREFORE BD=CD(CPCT)

ANGLE BAD=ANGLE CAD(CPCT)

HENCE AD BISECTS BOTH BC AND ANGLE A

Please Thanks all answer

Answer 2

Answer:

Angle ADB = ADC.

Step-by-step explanation:

The altitude of a triangle is defined as the perpendicular drawn from the vertex of the triangle to the opposite side.

Altitude BD is dividing triangle in two parts.

In triangles ADB and ADC

Angle ADB=Angle ADC This is due to the fact that BD is altitude.

Both are right angles.

So, we can say that

Angle  ADB = Angle ADC

So, by knowing the definition and properties of altitude of triangle, this can be determined.

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