✔✔1.In which of the following situation does the list of numbers involved make an arithmetic progression and why.??? ✔✔✔
a. The amount of air present in the cylinder when a vacuum pump removes 1 by 4 of the air remaining in the cylinder at a time.. ✔✔
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Answers
Answered by
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bro that will not be in an ap I can explain this you with an example;
let's take suppose that you have 100kg air in your cylinder then by removing one fourth of the air we get 75kg of the air left in the cylinder......
now we have 75 kg and again removing one fourth of the year we get 56.25kg of the air left in the cylinder.......
now we have 56.25 kg of the air and again remove in one fourth we get 42.19kg.....
now you will get the AP As given below;
100kg, 75kg, 56.25kg,42.19kg,........so on
as you can see the following is not in an ap so you can conclude that this will not be in AP ............
"that was all from my side hope this helps you"
PLZ MARK ME BRAINLIEST!!
let's take suppose that you have 100kg air in your cylinder then by removing one fourth of the air we get 75kg of the air left in the cylinder......
now we have 75 kg and again removing one fourth of the year we get 56.25kg of the air left in the cylinder.......
now we have 56.25 kg of the air and again remove in one fourth we get 42.19kg.....
now you will get the AP As given below;
100kg, 75kg, 56.25kg,42.19kg,........so on
as you can see the following is not in an ap so you can conclude that this will not be in AP ............
"that was all from my side hope this helps you"
PLZ MARK ME BRAINLIEST!!
Answered by
0
Answer:
thanks for free points
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