Question

1,In which of the following situations,does the list of numbers involved make an arithmetic progression ,a nd why? 1,the taxi fare after each km when the fare is rupees 15 for the first km and rupees 8 for each additional km.

Answer 1

Answer:

here a1 = 15

and d = 8

then AP = a, a+d a+2d...

AP = 15,23,31,39.....

Answer 2

Answer:

We can write the given condition as;

Taxi fare for 1 km = 15

Taxi fare for first 2 kms = 15 + 8 = 23

Taxi fare for first 3 kms = 23 + 8 = 31

Taxi fare for first 4 kms = 31 + 8 = 39

And so on……

Thus, 15, 23, 31, 39 … forms an A.P. Because every next term is 8 more than the preceding term.