Math, asked by ankitkumarever4u, 6 months ago

1. In which of the following situations, does the list of numbers involved make an arithmetic
progression, and why?
(i) The taxi fare after each km when the fare is 15 for the first km and 8 for each
additional km.​

Answers

Answered by yagnasrinadupuru
0

Solution \\ </p><p></p><p>given \: = a+a^2+a^3–1=0given=a+a2+a3–1=0 \\ </p><p></p><p>a+a^2+a^3=1a+a2+a3=1 \\ </p><p></p><p>Taking \:  ‘a’ \:  common \:  in  \: LHS. \\ </p><p></p><p>a(1+a+a^2)=1a(1+a+a2)=1 \\ </p><p></p><p>1+a+a^2=1/a1+a+a2=1/a ………..(1) \\ </p><p></p><p>Now  \: what  \: you need \:  to \:  find \:  is  \: a^3+1/a \\ </p><p></p><p>So  \: substitute  \: the  \: value  \: of  \: 1/a  \: from  \: equation (1) \\ </p><p></p><p>This \:  gives \:  us  \: a^3+ 1+a+a^2a3+1+a+a2 \\ </p><p></p><p>↪a^3+a^2+a+1↪a3+a2+a+1 \\ </p><p></p><p>↪1+1↪1+1 \\ </p><p></p><p>↪ 2↪2 \\ </p><p></p><p>So  \: 2 \:  is \:  the \:  required \:  answer. \\ </p><p></p><p>

Answered by BeautifulWitch
1

Answer:

We can write the given condition as;

Taxi fare for 1 km = 15

Taxi fare for first 2 kms = 15+8 = 23

Taxi fare for first 3 kms = 23+8 = 31

Taxi fare for first 4 kms = 31+8 = 39

And so on……

Thus, 15, 23, 31, 39 … forms an A.P. because every next term is 8 more than the preceding term.

Step-by-step explanation:

Hope this helps you ✌️

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