Math, asked by nithyaramesht890, 18 days ago

1) Interest for 1000 rupees is Monthly 20
rupees.
a.) What is the interest of 100 rupees for
one month?
b.) What is the rate of interest ? ​

Answers

Answered by krishnasingh18279
3

Answer:

Interest of Rs.100  = Rs.2/-

\bold{r = 2\%}r=2%

Step-by-step explanation:

Given,

Principal = 1000

Simple interest for one month = Rs.20/-

(a). Interest of 100 rupees for one month is

Interest of Rs. 1000 = Rs.20

Then,

Interest of Rs.100 = \frac{20}{1000}\times 100100020×100

Interest of Rs.100  = Rs.2/-

(b). SI = \frac{p\times r\times t}{100}SI=100p×r×t

20 = \frac{1000\times r\times 1}{100}20=1001000×r×1

r = \frac{100\times 20}{1000}r=1000100×20

\bold{r = 2\%}r=2%

Answered by narendrak69046
0

Answer:

a) 0.4 b) 0.4%

Step-by-step explanation:

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