Question

(1+iota)^4*(1+1/iota)^4=16 prove that

Answer 1

We know that if power are same and base are different also they are in multiply..

Therefore A^m*B^m=(AB)^m

iota=i

Now solve this by putting A=1+i & B=1+1/i

Therefore in the last we get 2^4=16

Hence proved