Question

1. _____ is a rectangle whose all sides are equal.
2. The amount of surface enclosed by a figure is called its ____.
3. For fencing the plot, we need to calculate its _____
4. Find the perimeter of Regular hexagon of side 8 cm
5. The perimeter of square is 40 cm, what is the side length?
6. Sachi takes 10 rounds of a rectangular park, 50 m long and 20 m wide. Find the total
distance covered by him.
7. Find the area in square meter of a piece of cloth 1m 25 cm wide and 2 m long.
8. The area of a rectangular garden 50 m long is 300 sq. m. Find the width of the garden. please answer fast

Answer 1

1. square.

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2.area

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3.perimeter.

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4.We know that perimeter of regular hexagon is 6×side

side=8cm.

Perimeter=6×8=48cm.

Perimeter of regular hexagon of side 8cm=48cm.

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5.We know that perimeter of square is 4 ×side. So perimeter =40cm

side=40/4=10cm

side of square=10cm.

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6.Given, length of rectangular park=50m.

width of rectangular park=20m.

Perimeter of rectangular park=2(l+w)

Perimeter of rectangular park=2(50+20)m

Perimeter of rectangular park=2(70)m

Perimeter of rectangular park=140m.

He took 10 rounds. So the total distance covered by him=10×Perimeter of rectangular park

Distance=10×140m=1400m.

Therefore,the total distance covered by him=1400m.

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7.Given,Length = 2 m= 2 x 100 cm

Length= 200 cm

Breadth =1 m 25 cm= 1 m + 25 m= 100 cm + 25 cm

Breadth = 125 cm

Area=Length × Breadth

Area= 200 x 125

Area= 25000 sq. cm

Area= 25000 cm

Area= 25000 x 1/10,000 m^2

Area= 2.5 m^2

Therefore, area in square meter of a piece of cloth 1m 25 cm wide and 2 m long=2.5m^2.

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8.Given,

Length of rectangle =50 m

Area of the rectangle=300sq.m

Area of rectangle = Length×Breadth

300 sq.m=50m×Breadth

50×Breadth=300

Breadth=300/50m

Breadth=6m.

Therefore,Breadth of rectangle garden is 6m.

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