Math, asked by dwijenpaharia7, 2 months ago

_1 is a zero of a polynomial p(x).p(x)=x⁶+k(_x)⁴_x³+3x. find the value of k

Answers

Answered by bson

0

Step-by-step explanation:

p(-1) =0

p(-1) = 1+k-(-1)-3 = k+2-3=0

k= 1

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