1 is a zero of polynomial x^2 a^2 - 3xa + 3x - 1 in x find the value(s) of a. || explanation please
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I do understand math
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if we put the zero in the equation we get zero
x²(a²) - 3xa + 3x -1 =0
1²(a²) - 3(1)a+3(1) - 1 =0
a² - 3a +3 -1 =0
a² - 3a +2=0
a²-2a-1a+2=0
a(a-2) -1( a-2)=0
(a-1)(a-2)=0
a-1=0. a=1
a-2=0. a=2
a=1,2
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