Question

1 is the in centre of ∆ ABC, <ABC-60" and <ACB-50° then <BIC is- ​

Answer 1

Step-by-step explanation:

BI and CI are the angle bisector

∴ ∠CBI = 30° and ∠BCI = 25°

In ΔBIC

∠CBI + ∠BCI + ∠BIC = 180°

30° + 25° + ∠BIC = 180°

∠BIC = 180° - 55°

∴ ∠BIC = 125°.

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