_1 is the root of x²_2x+1=0
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X2 - 1x - 1x + 1 = 0
X ( x-1)-1 (x-1)= 0
(X-1)(x-1) = 0
X-1 = 0
X= 1
so 1 is the root of that eqn.
X ( x-1)-1 (x-1)= 0
(X-1)(x-1) = 0
X-1 = 0
X= 1
so 1 is the root of that eqn.
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