Math, asked by Sanil55546, 9 months ago

1) It degree of the polynomial is
a) 0
b)1
c)any natural no:
d) not defined

2) If p(x) =x^2 - 2 square root 2x +1, then p(2square root 2) is equal to
a)0
b)1
c)4 square root 2
d)8 square root 2+1

3) If x^51 +51 is divided by x+1 then reminder is
a)0
b)1
c) 49
d)50

4) Check whether p(x)=x^3 -5x^2 +4x-3 is a multiple of g(x)=x-2

5)find the value of p, if (x+3) is a factor of polynomial 2x^2-3x^2 +p

6) factorise
a) x^3 - 6x^2 +11x -6





Answers

Answered by biligiri
2

Answer:

5) x+3 = 0 => x = -3 p(-3) = 0

p(-3) = 2*(-3)² - 3(-3) + p = 0

=> 2*9 + 9 + p = 0

=> 18 + 9 + p = 0

=> 27 + p = 0

=> p = -27

4) for x-2 to be a multiple of the given expression,

p (2) has to be zero [ x-2 = 0 , x = 2 ]

therefore p(2) = 2³ - 5*2² + 4*2 - 3

=> 8 - 20 + 8 - 3

=> - 7 ≠ 0, hence x-2 is not a multiple of

x³ - 5x² + 4x - 3

3) let x+1 = 0 => x = -1

when x⁵¹ + 51 is divided by x+1, the remainder

has to be equal to p(-1)

=> p(-1) = (-1)⁵¹ + 51

=> p(-1) = -1 + 51 [ when - 1 is raised to odd exponent, it remains as -1 ]

=> p(-1 ) = 50

therefore the remainder when x⁵¹ + 51 is divided by x+1 is + 50

Answered by Anonymous
2

Answer:

Answer:

5) x+3 = 0 => x = -3 p(-3) = 0

p(-3) = 2*(-3)² - 3(-3) + p = 0

=> 2*9 + 9 + p = 0

=> 18 + 9 + p = 0

=> 27 + p = 0

=> p = -27

4) for x-2 to be a multiple of the given expression,

p (2) has to be zero [ x-2 = 0 , x = 2 ]

therefore p(2) = 2³ - 5*2² + 4*2 - 3

=> 8 - 20 + 8 - 3

=> - 7 ≠ 0, hence x-2 is not a multiple of

x³ - 5x² + 4x - 3

3) let x+1 = 0 => x = -1

when x⁵¹ + 51 is divided by x+1, the remainder

has to be equal to p(-1)

=> p(-1) = (-1)⁵¹ + 51

=> p(-1) = -1 + 51 [ when - 1 is raised to odd exponent, it remains as -1 ]

=> p(-1 ) = 50

therefore the remainder when x⁵¹ + 51 is divided by x+1 is + 50

Similar questions