Question

1
iv) Principal =365,000, Rate%=9.5% p.a., Time =3 years
2
C 10 n​

Answer 1

Answer:

Simple Interest -

$= \frac{time \times rate \times principal}{100}$

$= \frac{365000 \times 95 \times 3}{100 \times 10} \\ \\ = 365 \times 95 \times 3 \\ \\ =104,025$

So, simple interest = ₹104025

Answer 2

Given :-

Principal = 365000

Rate = 9.5%

Time = 3 years

To Find :-

The Amount & Compound interest

Solution :-

We know that,

${\sf{A\: =\: P\: \bigg(1\: +\: {\dfrac{r}{100}}\bigg)^n}}$

On inserting the values in the formula

We get ,

${\sf{A\: =\: 365000\: \bigg(1\: +\: {\dfrac{9.5}{100}}\bigg)^3}}$

${\sf{\implies\: A\: =\: 365000\: \bigg({\dfrac{100\: +\: 9.5}{100}}\bigg)^3}}$

${\sf{\implies\: A\: =\: 365000\: \bigg({\dfrac{109.5}{100}}\bigg)^3}}$

${\sf{\implies\: A\: =\: 365000\: \times\: {\dfrac{109.5}{100}}\: \times\: {\dfrac{109.5}{100}}\: \times\: {\dfrac{109.5}{100}}}}$

${\sf{\implies\: A\: =\: \bold{479220.31}}}$

Therefore, Amount is 4,79,220.31

Compound interest = Amount - Principal

= 479220.31 - 365000

= 114220.31

Therefore, Compound interest is 1,14,220.31