1. Jeevan is 3 years younger than his brother Sasi. If the sum of their present ages is 19 years. What are their present ages? The length of a rectangle is 20m more than its width. If the perimeter of the rectangle is 100m,
Answers
Given:
1. Jeevan is 3 years younger than his brother Sasi. If the sum of their present ages is 19 years. What are their present ages?
2. The length of a rectangle is 20m more than its width. If the perimeter of the rectangle is 100m. Find the length and width of the rectangle?
To find:
1. What are their present ages?
2. Find the length and width of the rectangle?
Solution:
Let's say,
"J" → present age of Jeevan
"S" → present age of Sasi
Jeevan is 3 years younger than his brother Sasi, so we can form the equation as,
J = S - 3 . . . (1)
The sum of their present ages is 19 years, so we can form the equation as,
J + S = 19
on substituting the value of J from equation (1), we get
⇒ S - 3 + S = 19
⇒ 2S = 19 + 3
⇒ 2S = 22
⇒ S = 11 years
∴ Jeevan's present age = J = S - 3 = 11 - 3 = 8 years
Thus, the present age of Sasi is 11 years and that of Jeevan is 8 years old.
Let's say,
"L" → length of the rectangle
"W" → width of the rectangle
The length of a rectangle is 20m more than its width, so we can form the equation as,
L = W + 20 . . . (1)
The perimeter of the rectangle is 100 m, so we can form the equation as,
2[L + W] = 100 . . . [∵ Perimeter of a rectangle = 2×[length + width]]
on substituting the value of L from equation (1), we get
⇒ 2 × [W + 20 + W] = 100
⇒ W + 20 + W = 50
⇒ 2W = 50 - 20
⇒ 2W = 30
⇒ W = 15 m
∴ Length = L = W + 20 = 15 + 20 = 35 m
Thus, the length and width of the rectangle are 35 m and 15 m respectively.
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The length and width of a rectangle are in the ratio 5:3.find the dimensions of the rectangle if the perimeter is 112 cm.
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Answer:
for q no. 1
Step-by-step explanation: we take Jeevan's age as x and Sasi's age as y
so' x=y-3
x-y=-3
next,
x+y=19we add eq 1 and 2
x-y=-3
x+y=19 +
______
2x=22
x=22/2=11
x-y=-3
11-y=-3
-y=-3-11=-18
y=8
Jeevan's age = 11
Sasi's age = 8
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