1.Jogging at their normal speeds, Usha takes 3 minutes to jog once around a running track, while Tessie takes 4 minutes to do the same.
If Usha's normal jogging speed is 12 km/hr, what is Tessie's normal jogging speed?
Answers
Given : Jogging at their normal speeds, Usha takes 3 minutes to jog once around a running track,
Tessie takes 4 minutes to do the same.
Usha's normal jogging speed is 12 km/hr,
To Find : Tessie's normal jogging speed
Solution:
Usha takes 3 minutes to jog once around a running track,
Let say Track length = 12L m
Usha speed = 12L/3 = 4L m/s
Tessie takes 4 minutes to jog once around a running track,
Tessie speed = 12L/4 = 3L m/s
Usha speed : Tessie speed = 4L : 3L
=> Usha speed : Tessie speed = 4 : 3
Usha's normal jogging speed is 12 km/hr,
Tessie's normal jogging speed = T km/hr
=> 4/3 = 12/T
=> T = 9 km/hr
Tessie's normal jogging speed = 9 km/hr
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HELLO DEAR,
GIVEN:-
Usha takes 3 minutes to jog once around a running track.
Tessie takes 4 minutes to do the same.
Usha jogging speed = 12km/h
=( 10/3) m/s.
To find the jogging speed of Tessie.
SOLUTION:-
Let the total distance of jogging track = X.
So by using,
speed = distance / time.
Usha speed =( 10/3)m/s.
time = 3 minutes
= 180 s.
Speed = distance/time.
10/3 = X/ 180
X = (10×180)/3
= 600m.
Therefore speed of Tessie,
Speed= distance / time
Speed = 600/ 240
= 2.5 m/ s.
Speed of Tessie = 2.5 m/s.
To change it into km/h,
We have to multiple by 18/5.
2.5× 18/5 = 9 km/h.
Therefore , speed of Tessie = 9 km/h.