શોધો.
(1) (k + 1)x - 2(k + 4)x + 2k = 0; k R
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(k + 1)x - 2(k + 4)x + 2k = 0
kx + x - 2kx - 8x + 2k =0
-kx - 7x + 2k = 0
k(2-x) = 7x
k = 7x/(2-x)
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