Math, asked by gis0030, 2 days ago

1. kashi wants to fix a colorful ribbon around a painting which is 20cm long and 15cm wide. if she has 130 Cm ribbon how much ribbon will be needed to fix around the painting 4time​

Answers

Answered by ankits48828
0

Step-by-step explanation:

interest. Her annual income from these investments is 1280.00. How much did she invest at each rate.Jassi inherited 12000.00. She invested part of it at 10% and the rest at 12o p.a. simple interest. Her annual income from these investments is 1280.00. How much did she invest at each rate.Jassi inherited 12000.00. She invested part of it at 10% and the rest at 12o p.a. simple interest. Her annual income from these investments is 1280.00. How much did she invest at each rate.Jassi inherited 12000.00. She invested part of it at 10% and the rest at 12o p.a. simple interest. Her annual income from these investments is 1280.00. How much did she invest at each rate.Jassi inherited 12000.00. She invested part of it at 10% and the rest at 12o p.a. simple interest. Her annual income from these investments is 1280.00. How much did she invest at each Rates inherited 12000.00. She invested part of it at 10% and the rest at 12o p.a. simple interest. Her annual income from these investments is 1280.00. How much did she invest at each rate.Jassi inherited 12000.00. She invested part of it at 10% and the rest at 12o p.a. simple interest. Her annual income from these investments is 1280.00. How much did she invest at each rate.Jassi inherited 12000.00. She invested part of it at 10% and the rest at 12o p.a. simple interest. Her annual income from these investments is 1280.00. How much did she invest at each rate.Jassi inherited 12000.00. She invested part of it at 10% and the rest at 12o p.a. simple interest. Her annual income from these investments is 1280.00.rate How much did she invest at each rate.Jassi inherited 12000.00. She invested part of it at 10% and the rest at 12o p.a. simpl

Answered by PranavAgeeth
0

Answer:

Kashi would need 150 cm of ribbon extra in order to fix around the painting 4 times.

Step-by-step explanation:

l = 20 cm, b = 15 cm

Perimeter of the painting = 2 x (l+b)

                                          = 2 x (20+15)

                                          = 2 x 35

                                          = 70 cm

Length of ribbon required to fix around the painting 1 time = 70 cm

Length of ribbon required to fix around the painting 4 times = 70 x 4

                                                                                                    = 280 cm

Length of ribbon that Kashi already has = 130 cm

Length of ribbon that Kashi needs = 280 - 130

                                                         = 150 cm

∴ Kashi would need 150 cm of ribbon extra in order to fix around the painting 4 times.

Similar questions