1-kg block rests on a frictionless table and is connected by a light string to
another block of mass 2 kg. The string is passed over a pulley of negligible mass
and friction, with the 2 kg mass hanging vertically. What is the acceleration of the
masses?
a. 5 ms b. 6.53 m/s u. 4.5 m3 d. 20 ms?
Answers
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T=ma....(1)
2mg – T = 2ma.... (2)
...
so from 1&2
2mg = 3ma
:. a= 20/3
(m= 1kg & g=10)
2mg – T = 2ma.... (2)
...
so from 1&2
2mg = 3ma
:. a= 20/3
(m= 1kg & g=10)
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