Question

1 kg body explodes into three fragments. The ratio of their masses is 1 : 1 : 3. The fragments of same mass move perpendicular to each other with speeds 30 m/s-1, while the heavier part remains in the initial direction. The speed of heavier part is:

Answer 1

Answer:

10√2 (14.14)

Explanation:

Let the masses be m/5, m/5, 3m/5

Since the heavier part follows the initial direction, the momentum of the each part flying at right angles would be at 45° w.r.t to the third mass.

Therefore,

$m/5 (30cos45)+m/5(30cos45)=(3m/5)v\\6m/5+6m/5=(3m/5)v\\v=(12m/5)(5/3m)\\v=20/\sqrt{2}$

which is equal to $10\sqrt{2}$ or 14.14 m/s