Question

1 kg of ice at -10 degree celsius is mixed with 4.4 kg of water at 30 degree Celsius the final temperature of the mixture is back its specific heat of ice is 2900 joule per kg per Kelvin​

Answer 1

Answer:

correct option is d. 8.3 ℃

Answer 2

The final temperature of the mixture is 41.91⁰ C.

Explanation:

Given:

1 kg of ice at -10⁰ C

4.4 kg of water at 30⁰ C.

Specific heat = 2900 J kg/k

Latent heat of ice = 336 J kg/k

              mC ΔT = mC ΔT + mL

          ⇒ 2900 x 4.4 (T₂ - 30) = 2900 ( T₂ + 10) + 4.4 x 336

                                    ⇒ T₂ = 41.91 ⁰C

       After solving above equation,