Question

1 kg of water at 273 k is brought in contact with a heat reservoir at 373 k .then what is the change in entropy of water is temperatures reaches 373 k? (2)what is the change in entropy of the reservoir and the universe​

Answer 1

Answer:

1 kg water at 0°C is brought into contact with a heat reservoir at 90°C. When the water has reached 90°C,

Explanation:

Solution

Given:

Initial temperature, To = 0 °C = 273 K

Final temperature, T1 = 90 °C = 363 K

Mass of water, m = 1 Kg

Answer 2

The change in entropy of the reservoir the universe as 1.12KJ.

Explanation:

$T_{1}=273k$

$T_{2}=373k$

$m=1kg$

ΔE=$\frac{cm(T_{2}-T_{1})}{T_{2}}$

where, c-heat capacity of water=$4.1813\frac{KJ}{Kg*K}$

ΔE=$\frac{4.18131*(373-273)}{373}$

$=1.12KJ$