Question

1 kg sample of hard water shows the presence of 0.01 gram Ca + 2 ions what is the concentration of Ca+ 2 ions in PPM?

Answer 1

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Answer 2

Given:

1Kg of sample of hard water indicates the presence of 0.01g Ca⁺² ions.

To find:

Concentration of Ca⁺² ions in ppm.

Solution:

Hard water means the sample is contain CaCO₃.

mass of Ca⁺² present in sample = 0.01g

mass of sample of hard water = 1Kg = 1000g

To find the concentration of Ca⁺² ions in ppm formula used is

  ${{\text{ca^+^2(ppm)}}} = \left( {\frac{{mass of ca^+^2}}{{mass of solution}}}) \cdot {10^6}$${{\text{Ca}}^{{+2}}ppm} = {{ \left {\frac{{mass of Ca^+^2 }}{{mass of solution}}} \cdot {10^6}$

now putting all the values we get,

${{\text{Ca}}^{{+2}}ppm} = {{ \left {\frac{{0.01 }}{{1000}}} \cdot {10^6}$

Ca⁺²(ppm) = 10⁶⁻⁵ ppm

Ca⁺²(ppm) = 10ppm

So, the concentration of Ca⁺² ions in ppm present in the sample of 1Kg of hard water sample is 10ppm.