1 kilo of crab and a fish cost $111 in total. If the crab's price is $55 higher than the fish, how much does the fish cost?
Answers
Answered by
40
Answer:
$28
Step-by-step explanation:
let price of fish = $x
then price of crab =$x+$55
price of crab + price of fish = $111
X+X+55=111
2x=111-55
2x=56
X=28
X+55=83
price of crab =$28
price of fish = $
Answered by
5
Step-by-step explanation:
Given -
- Price of crab + Price of fish = $111
- Crab's price is $55 higher than the fish
To Find -
Price of fish
Now,
Let x be the price of fish.
Then,
The Crab's price is (x + $55)
According to the question -
- Price of crab + Price of fish = $111
It means,
= x + $55 + x = $111
= 2x = $111 - $55
= 2x = $56
= x = $56/2
- = x = $28
Hence,
The price of fish is $28
And
The price of crab is (x + $55)
= $28 + $55
= $83
Verification -
- Price of crab + Price of fish = $111
= $83 + $28 = $111
= $111 = $111
LHS = RHS
Hence,
Verified..
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