Math, asked by rahavibalafeb07, 10 months ago

1 kilo of crab and a fish cost $111 in total. If the crab's price is $55 higher than the fish, how much does the fish cost?​

Answers

Answered by Anonymous
40

Answer:

$28

Step-by-step explanation:

let price of fish = $x

then price of crab =$x+$55

price of crab + price of fish = $111

X+X+55=111

2x=111-55

2x=56

X=28

X+55=83

price of crab =$28

price of fish = $

Answered by TrickYwriTer
5

Step-by-step explanation:

Given -

  • Price of crab + Price of fish = $111
  • Crab's price is $55 higher than the fish

To Find -

Price of fish

Now,

Let x be the price of fish.

Then,

The Crab's price is (x + $55)

According to the question -

  • Price of crab + Price of fish = $111

It means,

= x + $55 + x = $111

= 2x = $111 - $55

= 2x = $56

= x = $56/2

  • = x = $28

Hence,

The price of fish is $28

And

The price of crab is (x + $55)

= $28 + $55

= $83

Verification -

  • Price of crab + Price of fish = $111

= $83 + $28 = $111

= $111 = $111

LHS = RHS

Hence,

Verified..

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