Chemistry, asked by NikitaBishnoi27, 8 months ago

1 L solution of N/2 HCl boiles into a beaker than calculate the new normality of HCl when its remain 600ml of 3.25g HCl

Answers

Answered by kushwahaaakash230

1

Answer:

N = 3.25g/2×600×10`³L`¹

= 3.25g/1200×10`³L`¹

= 0.0027×10³L

Explanation:

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