Science, asked by sauravharsh6508, 10 months ago

1. La belongs to group 3 while Hg belongsto group 12 and both belong to period 6of the periodic table. Write down thegeneral outer electronic configuration ofthe ten elements from La to Hg togetherusing orbital notation method.​

Answers

Answered by ChitranjanMahajan
16

The ten elements starting from La (Lanthanum) to Hg (Mercury) across period 6 are :

Lanthanum (La), Haffnium (Hf), Tantalum (Ta), Tungsten (W), Rhenium (Re), Osmium (Os), Iridium (Ir), Platinum (Pt), Aurum (Au), and Mercury (Hg).

• Electron configuration of an element is the representation of its number of electrons in the form of s, p, d, and f orbitals.

• Also, number of electrons in a neutral atom = Atomic number of the element

• The electrons are filled according to the Afbau's principle.

• The electronic configuration of the aforementioned elements are as follows :

La (57) - [Xe] 5d1 6s2

Hf (72) - [Xe] 4f14 5d2 6s2

Ta (73) - [Xe] 4f14 5d3 6s2

W (74) - [Xe] 4f14 5d4 6s2

Re (75) - [Xe] 4f14 5d5 6s2

Os (76) - [Xe] 4f14 5d6 6s2

Ir (77) - [Xe] 4f14 5d7 6s2

Pt (78) - [Xe] 4f14 5d9 6s1

Au (79) - [Xe] 4f14 5d10 6s1

Hg (80) - [Xe] 4f14 5d10 6s2

[Xe] represents 54 number of electrons as the atomic number of Xe is 54. Therefore, for convenience, 54 electrons are represented as [Xe].

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